#include using namespace std; int n, x[100005]; int main(){ cin >> n; for(int i = 1 ; i <= n ; ++ i) cin >> x[i]; long long int cnt = 0; for(int i =1 ; i <= n ; ++ i) { int j = i + 1; while(j <= n && x[j] == x[i]) j ++; int p = j - i; cnt += 1LL * p*(p+1)/2; i = j - 1; } cout << cnt << endl; return 0; }