#include using namespace std; ifstream in("sume2.in"); ofstream out("sume2.out"); long long int S[100004], n, m, temp, var; int main() { in >> n; for (int i = 1; i <= n; ++i) { in >> temp; S[i] = S[i - 1] + temp; } in >> m; for (int i = 1; i <= m; ++i) { in >> temp >> var; out << S[var] - S[temp - 1] << "\n"; } return 0; }